Antihydra nonhalting conjecture
Prove that, for the Collatz-like map H: N → N defined by H(x) = 3x/2 when x is even and H(x) = 3(x−1)/2 when x is odd, iterating H starting at x = 8 never yields strictly more than twice as many odd values as even values; equivalently, show that the 6-state, 2-symbol Turing machine with transition table 1RB1RA_0LC1LE_1LD1LC_1LA0LB_1LF1RE_---0RA (Antihydra) does not halt from the all-zero tape.
References
Antihydra (https://bbchallenge.org/#1{1RB1RA_0LC1LE_1LD1LC_1LA0LB_1LF1RE_---0RA}; see Turing machine notation, Section~\ref{sec:TMs}) is a machine that does not halt from the all-zero tape if and only if the following Collatz-reminiscent conjecture holds: Consider the Collatz-like map $H: \mathbb{N} \to \mathbb{N}$ defined by $H(x) = 3\frac{x}{2}$ if $x$ is even and $H(x) = 3\frac{x-1}{2}$ if $x$ is odd. Iterating $H$ from $x=8$, there are never (strictly) more than twice as many odd numbers as even numbers.