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Cross commutators of Rudin's submodules

Published 30 Nov 2013 in math.FA | (1312.0070v2)

Abstract: Let $b(z) = \prod_{n=1}\infty \frac{-\bar{\alpha}n}{|\alpha_n|} \frac{z - \alpha_n}{1 - \bar{\alpha}_n z}$, where $\sum{n=1}\infty (1 - |\alpha_n|) <\infty$, be the Blaschke product with zeros at $\alpha_n \in \mathbb{D} \setminus {0}$. Then $\cls = \vee_{n=1}\infty \big(zn H2(\mathbb{D})\big) \otimes \big(\prod_{k=n}\infty \frac{-\bar{\alpha}n}{|\alpha_n|} \frac{z - \alpha_n}{1 - \bar{\alpha}_n z} H2(\mathbb{D})\big)$ is a joint $(M{z_1}, M_{z_2})$ invariant subspace of the Hardy space $H2(\mathbb{D}2) \cong H2(\mathbb{D}) \otimes H2(\mathbb{D})$. This class of subspaces was originally introduced by Rudin in the context of infinite cardinality of generating sets of shift invariant subspaces of $H2(\mathbb{D}2)$. \noindent In this paper we prove that for a Rudin invariant subspace $\cls$ of $H2(\mathbb{D}2)$, the cross commutator $[(P_{\cls} M_{z_1}|{\cls})*, M{z_2}|{\cls}] = (P{\cls} M_{z_1} |{\cls})* (M{z_2}|{\cls}) - (M{z_2}|{\cls}) (P{\cls} M_{z_1}|_{\cls})*$ is not compact. Consequently, Rudin's invariant subspaces are both infinitely generated and not essentially doubly commuting.

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