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Pythagorean powers of hypercubes

Published 21 Jan 2015 in math.FA and math.MG | (1501.05213v2)

Abstract: For $n\in \mathbb{N}$ consider the $n$-dimensional hypercube as equal to the vector space $\mathbb{F}2n$, where $\mathbb{F}_2$ is the field of size two. Endow $\mathbb{F}_2n$ with the Hamming metric, i.e., with the metric induced by the $\ell_1n$ norm when one identifies $\mathbb{F}_2n$ with ${0,1}n\subseteq \mathbb{R}n$. Denote by $\ell_2n(\mathbb{F}_2n)$ the $n$-fold Pythagorean product of $\mathbb{F}_2n$, i.e., the space of all $x=(x_1,\ldots,x_n)\in \prod{j=1}n \mathbb{F}2n$, equipped with the metric $$ \forall\, x,y\in \prod{j=1}n \mathbb{F}2n,\qquad d{\ell_2n(\mathbb{F}_2n)}(x,y)= \sqrt{ |x_1-y_1|12+\ldots+|x_n-y_n|_12}. $$ It is shown here that the bi-Lipschitz distortion of any embedding of $\ell_2n(\mathbb{F}_2n)$ into $L_1$ is at least a constant multiple of $\sqrt{n}$. This is achieved through the following new bi-Lipschitz invariant, which is a metric version of (a slight variant of) a linear inequality of Kwapie{\'n} and Sch\"utt (1989). Letting ${e{jk}}{j,k\in {1,\ldots,n}}$ denote the standard basis of the space of all $n$ by $n$ matrices $M_n(\mathbb{F}_2)$, say that a metric space $(X,d_X)$ is a KS space if there exists $C=C(X)>0$ such that for every $n\in 2\mathbb{N}$, every mapping $f:M_n(\mathbb{F}_2)\to X$ satisfies \begin{equation*}\label{eq:metric KS abstract} \frac{1}{n}\sum{j=1}n\mathbb{E}\left[d_X\Big(f\Big(x+\sum_{k=1}ne_{jk}\Big),f(x)\Big)\right]\le C \mathbb{E}\left[d_X\Big(f\Big(x+\sum_{j=1}ne_{jk_j}\Big),f(x)\Big)\right], \end{equation*} where the expectations above are with respect to $x\in M_n(\mathbb{F}_2)$ and $k=(k_1,\ldots,k_n)\in {1,\ldots,n}n$ chosen uniformly at random. It is shown here that $L_1$ is a KS space (with $C= 2e2/(e2-1)$, which is best possible), implying the above nonembeddability statement. Links to the Ribe program are discussed, as well as related open problems.

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