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An analog of Hölder's inequality for the spectral radius of Hadamard products

Published 3 Dec 2017 in math.SP | (1712.00700v2)

Abstract: We prove new inequalities related to the spectral radius $\rho$ of Hadamard products (denoted by $\circ$) of complex matrices. Let $p,q\in [1,\infty]$ satisfy $\frac{1}{p}+\frac{1}{q}=1$, we show an analog of H\"older's inequality on the space of $n\times n$ complex matrices $$\rho(A\circ B) \le \rho(|A|{\circ p}){\frac{1}{p}} \rho(|B|{\circ q}){\frac{1}{q}} \quad \text{for all $A,B\in \mathbb{C}{n\times n}$,} $$ where $|\cdot|$ denotes entry-wise absolute values, and $(\cdot){\circ p}$ represents the entry-wise Hadamard power. We derive a sharper inequality for the special case $p=q=2$. Given $A,B\in \mathbb{C}{n\times n}$, for some $\beta \in (0,1]$ depending on $A$ and $B$, $$\rho(A\circ B) \le \beta \rho(|A\circ A|){\frac{1}{2}} \rho(|B\circ B|){\frac{1}{2}}.$$ Analysis for another special case $p=1$ and $q=\infty$ is also included.

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