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On $t$-relaxed 2-distant circular coloring of graphs

Published 16 Oct 2019 in math.CO | (1910.07321v1)

Abstract: Let $k$ be an positive integer. For any two integers $i$ and $j$ in ${0,1,\dots,k-1}$, let $|i-j|_k=\min{|i-j|,k-|i-j|}$ be the circular distance between $i$ and $j$. Let $t$ be a nonnegative integer. Suppose $f$ is a mapping from $V(G)$ to ${0,1,\dots,k-1}$. If adjacent vertices receive different integers, and for each vertex $u$ of $G$, the number of neighbors $v$ of $u$ with $|f(u)-f(v)|_k=1$ is at most $t$, then $f$ is called a $t$-relaxed 2-distant circular $k$-coloring, or simply a $(\frac{k}{2},t)*$-coloring of $G$. If $G$ has a $(\frac{k}{2},t)*$-coloring, then $G$ is called $(\frac{k}{2},t)*$-colorable. In this paper, we prove that, for any two fixed integers $k$ and $t$ with $k\geq2$ and $t\geq1$, deciding whether $G$ is $(\frac{k}{2},t)*$-colorable is NP-complete expect the case $k=2$ and the case $k=3$ and $t\leq3$, which are polynomially solvable. For any outerplanar graph $G$, e show that all outerplanar graphs are $(\frac{5}{2},4)*$-colorable, we prove that there is no fixed positive integer $t$ such that all outerplanar graphs are $(\frac{4}{2},t)*$-colorable.

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