Cycles in Color-Critical Graphs
Abstract: Tuza [1992] proved that a graph with no cycles of length congruent to $1$ modulo $k$ is $k$-colorable. We prove that if a graph $G$ has an edge $e$ such that $G-e$ is $k$-colorable and $G$ is not, then for $2\leq r\leq k$, the edge $e$ lies in at least $\prod_{i=1}{r-1}(k-i)$ cycles of length $1\mod r$ in $G$, and $G-e$ contains at least $\frac{1}{2}\prod_{i=1}{r-1}(k-i)$ cycles of length $0 \mod r$. A $(k,d)$-coloring of $G$ is a homomorphism from $G$ to the graph $K_{k:d}$ with vertex set $\mathbb{Z}_{k}$ defined by making $i$ and $j$ adjacent if $d\leq j-i \leq k-d$. When $k$ and $d$ are relatively prime, define $s$ by $sd\equiv 1\mod k$. A result of Zhu [2002] implies that $G$ is $(k,d)$-colorable when $G$ has no cycle $C$ with length congruent to $is$ modulo $k$ for any $i\in {1,\ldots,2d-1}$. In fact, only $d$ classes need be excluded: we prove that if $G-e$ is $(k,d)$-colorable and $G$ is not, then $e$ lies in at least one cycle with length congruent to $is\mod k$ for some $i$ in ${1,\ldots,d}$. Furthermore, if this does not occur with $i\in{1,\ldots,d-1}$, then $e$ lies in at least two cycles with length $1\mod k$ and $G-e$ contains a cycle of length $0 \mod k$.
Paper Prompts
Sign up for free to create and run prompts on this paper using GPT-5.
Top Community Prompts
Collections
Sign up for free to add this paper to one or more collections.