The Chromatic Number of $\mathbb{R}^{n}$ with Multiple Forbidden Distances
Abstract: Let $A\subset\mathbb{R}{>0}$ be a finite set of distances, and let $G{A}(\mathbb{R}{n})$ be the graph with vertex set $\mathbb{R}{n}$ and edge set ${(x,y)\in\mathbb{R}{n}:\ |x-y|{2}\in A}$, and let $\chi(\mathbb{R}{n},A)=\chi\left(G{A}(\mathbb{R}{n})\right)$. Erd\H{o}s asked about the growth rate of the $m$-distance chromatic number [ \bar{\chi}(\mathbb{R}{n};m)=\max_{|A|=m}\chi(\mathbb{R}{n},A). ] We improve the best existing lower bound for $\bar{\chi}(\mathbb{R}{n};m)$, and show that [ \bar{\chi}(\mathbb{R}{n};m)\geq\left(\Gamma_{\chi}\sqrt{m+1}+o(1)\right){n} ] where $\Gamma_{\chi}=0.79983\dots$ is an explicit constant. Our full result is more general, and applies to cliques in this graph. Let $\chi_{k}(G)$ denote the minimum number of colors needed to color $G$ so that no color contains a $(k+1)$-clique, and let $\bar{\chi}{k}(\mathbb{R}{n};m)$ denote the largest value this takes for any distance set of size $m$ . Using the Partition Rank Method, we show that [ \bar{\chi}{k}(\mathbb{R}{n};m)>\left(\Gamma_{\chi}\sqrt{\frac{m+1}{k}}+o(1)\right){n}. ]
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