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Counting oriented trees in digraphs with large minimum semidegree

Published 24 May 2023 in math.CO | (2305.15101v2)

Abstract: Let $T$ be an oriented tree on $n$ vertices with maximum degree at most $e{o(\sqrt{\log n})}$. If $G$ is a digraph on $n$ vertices with minimum semidegree $\delta0(G)\geq(\frac12+o(1))n$, then $G$ contains $T$ as a spanning tree, as recently shown by Kathapurkar and Montgomery (in fact, they only require maximum degree $o(n/\log n)$). This generalizes the corresponding result by Koml\'os, S\'ark\"ozy and Szemer\'edi for graphs. We investigate the natural question how many copies of $T$ the digraph $G$ contains. Our main result states that every such $G$ contains at least $|Aut(T)|{-1}(\frac12-o(1))nn!$ copies of $T$, which is optimal. This implies the analogous result in the undirected case.

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