Dimension of diagonal self-affine sets and measures via non-conformal partitions
Abstract: Let $\Phi:=\left{ (x_{1},...,x_{d})\rightarrow\left(r_{i,1}x_{1}+a_{i,1},...,r_{i,d}x_{d}+a_{i,d}\right)\right} {i\in\Lambda}$ be an affine diagonal IFS on $\mathbb{R}{d}$. Suppose that for each $1\le j{1}<j_{2}\le d$ there exists $i\in\Lambda$ so that $|r_{i,j_{1}}|\ne|r_{i,j_{2}}|$, and that for each $1\le j\le d$ the IFS $\left{ t\rightarrow r_{i,j}t+a_{i,j}\right} {i\in\Lambda}$ on the real line is exponentially separated. Under these assumptions we show that the Hausdorff dimension of the attractor of $\Phi$ is equal to $\min\left{ \dim{A}\Phi,d\right} $, where $\dim_{A}\Phi$ is the affinity dimension. This follows from a result regarding self-affine measures, which says that, under the additional assumption that the linear parts of the maps in $\Phi$ are all contained in a $1$-dimensional subgroup, the dimension of an associated self-affine measure $\mu$ is equal to the minimum of its Lyapunov dimension and $d$. Most of the proof is dedicated to an entropy increase result for convolutions of $\mu$ with general measures $\theta$ of non-negligible entropy, where entropy is measured with respect to non-conformal partitions corresponding to the Lyapunov exponents of $\mu$. It turns out that with respect to these partitions, the entropy across scales of repeated self-convolutions of $\theta$ behaves quite differently compared to the conformal case. The analysis of this non-conformal multi-scale entropy is the main ingredient of the proof, and is also the main novelty of this paper.
Paper Prompts
Sign up for free to create and run prompts on this paper using GPT-5.
Top Community Prompts
Collections
Sign up for free to add this paper to one or more collections.