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Degree $5$ Fibonacci Sums via the Gelin-Cesàro Identity

Published 20 Sep 2023 in math.CO | (2309.13074v3)

Abstract: Let $F_k$ be the $k$th Fibonacci number. Let $(G_k){k\in\mathbb Z}$ be any sequence obeying the recurrence relation of the Fibonacci numbers. We employ the Gerin-Ces`aro identity and an identity of Brousseau to evaluate the following sums: $\sum{j=1}n{(\pm 1){j - 1}G_j5}$, $\sum_{j = 1}n {G_{j - 1} G_{j} G_{j + 1} G_{j + 2} G_{j + m} }$, $\sum_{j = 1}n {(-F_{m - 3}){n - j} ( F_{m + 2} )j G_{j - 1} G_{j} G_{j + 1} G_{j + 2} G_{j + m} }$, and $\sum_{j = 1}n {(-F_{m + 2}){n - 2}F_{m - 3}jG_{j + m} \left( {G_{j - 2} G_{j - 1} G_j G_{j + 1} G_{j + 2} G_{j + 3} } \right){ - 1} }$. Among other results, we evaluate the sum and alternating sum of products of five consectutive Fibonacci-like numbers, namely $\sum_{j = 1}n {\left( { \pm 1} \right){j - 1} G_j G_{j + 1} G_{j + 2} G_{j + 3} G_{j + 4} }$.

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