Layered permutations determine the exponential growth rate of max principal specializations
Prove that the exponential growth rate of max_{w∈S_n} 𝛶_w equals the growth rate of the maximum over layered permutations, i.e., lim_{n→∞} (1/n^2) log_2 max_{w∈S_n} 𝛶_w = lim_{n→∞} (1/n^2) log_2 max_{w layered} 𝛶_w ≈ 0.29.
References
Conjecture The maximum of $\Upsilon_w$ over layered permutations has the same exponential growth rate as the maximum over the whole $S_n$, that is, $$\lim_{n\to \infty} \frac{1}{n2} \log_2 \,\max_{w \in S_n} \Upsilon_w \,=\, \lim_{n\to \infty} \frac{1}{n2} \log_2 \,\max_{w \text{ layered} \Upsilon_w \,\approx\, 0.29, $$ where the layered limit was computed in . In other words, any potential improvement over layered permutations is subexponential in $n2$.
— Computation and sampling for Schubert specializations
(2603.20104 - Anderson et al., 20 Mar 2026) in Section 6.6