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Products of Differences over Arbitrary Finite Fields

Published 18 May 2017 in math.CO and math.NT | (1705.06581v3)

Abstract: There exists an absolute constant $\delta > 0$ such that for all $q$ and all subsets $A \subseteq \mathbb{F}_q$ of the finite field with $q$ elements, if $|A| > q{2/3 - \delta}$, then [ |(A-A)(A-A)| = |{ (a -b) (c-d) : a,b,c,d \in A}| > \frac{q}{2}. ] Any $\delta < 1/13,542$ suffices for sufficiently large $q$. This improves the condition $|A| > q{2/3}$, due to Bennett, Hart, Iosevich, Pakianathan, and Rudnev, that is typical for such questions. Our proof is based on a qualitatively optimal characterisation of sets $A,X \subseteq \mathbb{F}_q$ for which the number of solutions to the equation [ (a_1-a_2) = x (a_3-a_4) \, , \; a_1,a_2, a_3, a_4 \in A, x \in X ] is nearly maximum. A key ingredient is determining exact algebraic structure of sets $A, X$ for which $|A + XA|$ is nearly minimum, which refines a result of Bourgain and Glibichuk using work of Gill, Helfgott, and Tao. We also prove a stronger statement for [ (A-B)(C-D) = { (a -b) (c-d) : a \in A, b \in B, c \in C, d \in D} ] when $A,B,C,D$ are sets in a prime field, generalising a result of Roche-Newton, Rudnev, Shkredov, and the authors.

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